in sports science they stated that mj's free throw line dunk in the dunk contest lasted .92 seconds
so i am just pondering here
i'll say you need an extra inch for every inch one is shorter than MJ to dunk from free throw
6'6 -mj 40inch vert for a free throw lane dunk
6'5 - 41 inch
6'4 -42inch
6'3-43inch
6'2-44inch
6'1-45inch
6'0-46inch
this is not adding in the account of speed or reach
but gonna need ~46inch vertical b4 i do a free throw lane dunk
interesting..
5'11 - 47
5'10 - 48
5'09 - 49 <- t-dub status off two feet
i dno man, seems like you are definitely in the right ballpark here.. reach really screws all of this data up though, and for the most part you'd have to be a single leg jumper..
regardless, those make sense.
is there a formula?? a trajectory formula ( have not taken physics yet haha) would be smart...but as i have not gotten that far in my education..idk 1
ok freethrow is 15ft right?
rim is 10ft up right?
reach is 94inches on me
so to dunk you need 10'5 i think and that's 125inches in the air right?
so my hand need to be 31inches in the air when i have traveled 15feet (obviously harder 2 do with a ball but let's make it simpler)
alright this is where i am stuck haha i did'nt take physics so i don't know how to do that yet
http://www.mathisfunforum.com/viewtopic.php?id=1673 --damn it i hate trigonometry but here goes
http://answers.yahoo.com/question/index?qid=20100327132701AAa49tf -- bad sources have this problem giving had time
so i am guessing i'll use a 45degree angle in the jump right? cuz that'
anyway i am gonna hit my geometry book for a quick second as i just remeber arching circles..i think i can make it into an arch then maybe i'll find the answer